2y^2+14(y+3)=198

Solution for 2y^2+14(y+3)=198 equation:

2y^2+14(y+3)=198

We move all terms to the left:

2y^2+14(y+3)-(198)=0

We multiply parentheses

2y^2+14y+42-198=0

We add all the numbers together, and all the variables

2y^2+14y-156=0

a = 2; b = 14; c = -156;
Δ = b2-4ac
Δ = 142-4·2·(-156)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-38}{2*2}=\frac{-52}{4}
=-13
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+38}{2*2}=\frac{24}{4}
=6
$